Ans.
Let us consider a rectangular plate having edges of lengths a and b respectively. This rectangular plate hangs vertically from the edge of length a . Let M be the total mass of the rectangular plate and G be the centre of gravity of the plate.

(i) Time period for small oscillation:
Let I be the moment of inertia of the plate about the horizontal axis through the point of suspension O and perpendicular to the plate lying in the vertical plane.
\displaystyle{I=\frac{1}{3}Mb^2}
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Now the time period of small oscillation is
\displaystyle{T=2\pi\sqrt{\frac{I}{Mg\left(OG\right)}}}
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where, g is the acceleration due to gravity.
From Fig.1 we get, OG=\frac{b}{2}
therefore, \displaystyle{T=2\pi\sqrt{\frac{I}{Mg\left(\frac{b}{2}\right)}}}
or, \displaystyle{T=2\pi\sqrt{\frac{\frac{1}{3}Mb^2}{Mg\left(\frac{b}{2}\right)}}}
or, \displaystyle{T=2\pi\sqrt{\frac{2b}{3g}}}\tag{1}
(ii) Length of the equivalent simple pendulum:
Let, L be the length of the equivalent simple pendulum, then
\displaystyle{T=2\pi\sqrt{\frac{L}{g}}}
Comparing with the equation (1), we get
\displaystyle{L=\frac{2}{3}b}